(4^x)+(2^1+2x)=50

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Solution for (4^x)+(2^1+2x)=50 equation: 



(4^x)+(2^1+2x)=50

We move all terms to the left:

(4^x)+(2^1+2x)-(50)=0

We get rid of parentheses

4^x+2x-50+2^1=0

We add all the numbers together, and all the variables

2x+4^x-48=0

We move all terms containing x to the left, all other terms to the right

2x+4^x=48

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